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2004 Club Championship Round 4

by on October 29, 2004

Lawson,B (2036) – Bonin,J (2380) [A65]

Queens CC Jamaica (4), 29.10.2004

1.d4 Nf6 2.c4 g6 3.Nc3 Bg7 4.e4 d6 5.f3 0–0 6.Bg5 c5 7.d5 h6 8.Be3 e6 9.Qd2 exd5 10.cxd5 a6 11.Rb1 11 Rc1 is Jussupow (2645) – Gelfand (2690), 0–1 in 54 (Munich, 1993). Sadler (2650) also played it twice in 1998 against Thipsey (2515), 1–0, and against Bates (2430), 1/2 in 33. 11 Bd3 and 11 Nge2 have also been tried, though less often. [11.Bxh6 Nxe4 12.Nxe4 Qh4+ 13.g3 Qxh6 14.Qxh6 Bxh6 15.Nxd6 and Fritz likes White.] 11…b5 12.b4 cxb4 13.Rxb4 Qa5 14.Rb3 Nbd7 15.a4 bxa4 16.Ra3 Nc5 17.Bxc5 Fritz prefers 17 Nxa4 with an equal game. 17…Qxc5 18.Rxa4 Bd7 19.Rc4 Qa3 20.Bd3 Rfc8 21.Nb1 Qa1 22.Rxc8+ Rxc8 23.Ne2 Bb5 24.0–0 Nd7 25.Bxb5 axb5 26.Qb4 Qb2 27.Qxb2 Bxb2 28.Rd1 b4 29.Nd2 Rc2 30.Kf1 Nc5 31.f4 31 Kf2 is better, but White would still be hard pressed to hold off the b-pawn. 31…Bc3 32.Nc4 Nxe4 33.Ng3 Nd2+ 34.Nxd2 Rxd2 35.Rxd2 Bxd2 36.Ke2 Bxf4 37.Kd3 Bxg3 38.hxg3 Kg7 39.Kc4 Kf6 40.Kxb4 Ke5 41.Kc4 f5 0–1

Bierkens,P (2237) – Simonaitis,A (1921) [C23]

Queens CC Jamaica (4), 29.10.2004

1.e4 e5 2.Bc4 d6 3.f4 Nf6 4.d3 Be7 5.Nf3 c6 5.. Bg4, 5.. Nbd7, and 5.. Nc6 have been played previously. 6.fxe5 dxe5 7.Nxe5?? Overlooking the point of Black’s sneaky 5th. Though White struggles on for 74 moves, the fight is essentially over on the 7th. 7…Qa5+ 8.Nc3 Qxe5 9.0–0 0–0 10.d4 Qh5 11.Qd3 b5 12.Bb3 b4 13.Ne2 Ba6 14.Bc4 Bxc4 15.Qxc4 Nxe4 16.Qd3 f5 17.Nf4 Qf7 18.Be3 Nd7 19.g4 Nb6 20.gxf5 Qxf5 21.Rae1 Bh4 22.Rd1 Kh8 23.Kh1 Rae8 24.Ng2 Nf2+ 25.Bxf2 Qxd3 26.Rxd3 Rxf2 27.Rxf2 Bxf2 28.Rd2 Rf8 29.h3 Nc4 30.Re2 Bxd4 31.Nf4 Bb6 32.Nd3 c5 33.Re4 Nd6 34.Re5 Nc4 35.Re4 Nd2 36.Re2 Nf3 37.Kg2 Nd4 38.Rd2 h6 39.c3 Nf3 40.Re2 Nh4+ 41.Kg3 Rf3+ 42.Kxh4 Rxd3 43.cxb4 cxb4 44.b3 Kh7 45.Kg4 Kg6 46.Re6+ Kf7 47.Re2 Bc7 48.Rc2 Bd6 49.Rc6 g6 50.Ra6 Rg3+ 51.Kh4 g5+ 52.Kh5 Rxh3+ 53.Kg4 Rh4+ 54.Kf3 Bc5 55.Rc6 Bb6 56.Kg3 Kg7 57.Re6 Rh1 58.Kg4 Ra1 59.Kf5 Rf1+ 60.Kg4 Rf2 61.Rc6 Rxa2 62.Kf5 Rf2+ 63.Kg4 Rf4+ 64.Kg3 Rf6 65.Rc4 a5 66.Kg2 Kg6 67.Kg3 h5 68.Kg2 g4 69.Rc8 Kg5 70.Rc1 h4 71.Rc8 Rf2+ 72.Kh1 Kf4 73.Rc4+ Kg3 74.Rc1 Rh2# 0–1

Guevara,R (2023) – Drobbin,M (1958) [D00]

Queens CC Jamaica (4), 29.10.2004

1.d4 Nf6 2.Bg5 d5 3.Bxf6 exf6 4.e3 Bf5 5.Ne2 c6 6.Nd2 6 Ng3 is typically played first. 6…Nd7 7.Ng3 Bg6 8.c4 dxc4 9.Bxc4 Nb6 10.Bb3 Bd6 11.0–0 0–0 12.Nde4 Be7 13.Qf3 Qc7 14.h4 h6 15.Qg4 Qd7?? 16.Qxg6 Nd5 17.Qf5 Qd8 18.Bxd5 cxd5 19.Nc3 Bd6 20.Qxd5 Bxg3 21.Qxd8 Bxf2+ 22.Rxf2 Raxd8 23.Rd2 Rfe8 24.Kf2 f5 25.d5 a6 26.a4 Rd6 27.a5 f6 28.h5 Kf7 29.Ra4 Re5 30.Rb4 Rd7 31.Rb6 f4 32.exf4 Rxh5 33.Ne4 Rhxd5 34.Nd6+ Ke6 35.Re2+ 1–0

Arluck,W (2052) – Waxman,M (1947) [A41]

Queens CC Jamaica (4), 29.10.2004

1.d4 d6 2.Nf3 Bg4 3.c3 Nf6 4.Qb3 Qc8 5.Bg5 Nbd7 5.. g6, 6 Bxf6 exf6 was the continuation in Gutman (2450) – Davies (2360), Lone Pine 1981, 1–0 in 26. 6.Nbd2 e6 7.e4 Be7 8.h3 Bh5 9.Bd3 c6 10.g4 Bg6 11.Nh4 d5 12.Nxg6 hxg6 13.exd5 cxd5 14.0–0–0 Qc7 15.Kb1 0–0–0 16.c4 Kb8 17.Rc1 Qa5 18.c5 Rc8 19.Bb5 Rhd8 [19…Ka8 20.Bxd7 Nxd7 21.Bxe7 Qxd2=] 20.Nf3 Qc7 (Diagram)


21.Bxd7 [21.Ba6!! Ka8 22.Bf4!+-] 21…Qxd7 22.Ne5 [22.c6! Rxc6 23.Ne5+-] 22…Qe8 23.Bf4 [23.c6! Rc7 24.Bf4 Bd6 25.g5+-] 23…Ka8 24.c6 Fritz thought this was strong for the past two moves, but here it thinks it’s weak and squanders White’s advantage. Instead, 24 Rc2 keeps White comfortably ahead. 24…bxc6 25.Qa4 c5 26.Qxe8 Rxe8 27.Nxf7 c4 [27…Ne4! 28.Be3 cxd4 29.Bxd4 Bf6 and Fritz gives Black a slight plus here.] 28.Ne5 Ne4 29.f3 g5 30.Be3 Nd6 31.Bd2 Bf6 32.Rce1 Nb5 33.Bc3 Rc7 34.Kc2 Rf8 35.Rhf1 Rh8 36.Rh1 Rf8 37.Ng6 Rff7 38.Rd1 Nxc3 39.bxc3 Be7 40.Rhf1 Rf6 41.Ne5 Bd6 42.Rde1 Re7 43.Rf2 Kb7 44.Kd2 Rh6 45.h4? 45 Rh2 with a likely draw. 45…Bxe5 46.Rxe5 gxh4 47.g5 Rg6? Entombing the Rook. 47.. Rh8 keeps Black in the driver’s seat. 48.f4 Kc6 49.Rh2 Kd6 50.Ke3 Re8 51.Rxh4 Rb8 52.Rh2 a5 53.Kf3 a4 54.Kg4 a3 55.f5 1–0

Cruz,K (1700) – Felber,J (2046) [B10]

Queens CC Jamaica (4), 29.10.2004

1.e4 c6 2.Nc3 d5 3.Qf3 dxe4 4.Nxe4 Nd7 5.b3 Ndf6 6.Nxf6+ Nxf6 7.Bb2 g6 Changing up from 7.. Qc7 of Cruz – Felber, ’02 Queens CC, 0–1 in 44. 8.Bd3 8 h3 is Fuller (2335) – Berg (2375), drawn in 14 in 1984. 8…Bg7 9.Qe2 0–0 10.Nf3 Bg4 11.h3 Bxf3 12.Qxf3 Qc7 13.0–0 Rad8 14.Rad1 Rd7 15.Rfe1 Nh5 16.Bxg7 Nxg7 17.Qe2 Ne6 18.Bc4 Nd4 19.Qe4 b5 20.Bd3 Ne6 21.Qe5 Qd8 22.Be4 The complications don’t work out in White’s favor. Fritz likes 22 Qc3= 22…Rxd2 23.Rxd2 Qxd2 24.Bxc6 b4 25.Re2 Qd1+ 26.Re1 Qxc2 27.Bd7 Nc5 28.Qxe7 Nxd7 29.Qxd7 Qxa2 30.Qd5 a5 31.Re4 Qa1+ 32.Kh2 h5 33.Re7 Qf6 34.Ra7 Qxf2 35.Rxa5 Qf4+ 36.Kh1 Kh7 37.Qe5 Qf2 38.Qc5 Qf1+ 39.Kh2 Qf4+ 40.Kg1 Rd8 41.Ra1 Qd4+ 42.Qxd4 Rxd4 43.Ra7 Rf4 44.Rb7 h4 45.Rd7 Kg7 46.Rd3 Kf6 47.g3 Giving Black a passer certainly doesn’t help, but it’s hard to find anything better at this point. 47…hxg3 48.Rxg3 Ke5 49.Kg2 Ke4 50.Kg1 Rf3 51.Rg4+ Ke3 52.Rxb4 Rxh3 53.Rb7 f5 54.Re7+ Kf4 55.b4 Rb3 56.Rb7 g5 57.b5 g4 58.b6 g3 59.Rd7 Rxb6 60.Rd4+ 0–1

Four exchange sacks in one game!

Pierre,A (1643) – Frumkin,E (2024) [B07]

Queens CC Jamaica (4), 29.10.2004

1.e4 d6 2.d4 Nf6 3.f3 d5 4.Nc3 e6 5.Bg5 Be7 6.Qd2 h6 6.. a6 is Disconzi da Silva (2370) – Milos (2560), 61st Brazil Ch. (1995), 0–1 in 43. 7.Be3 Bb4 8.e5 Nfd7 9.f4 c5 10.Nf3 Qa5 11.Be2 Nc6 12.0–0 c4 13.g4 Nb6 14.a4 14 a3 = 14…Bd7 15.Nh4 Nxa4 16.Qc1 Bxc3 17.Rxa4 Exchange sack #1 17…Qxa4 18.bxc3 Qa5 19.Qe1 g6 20.f5 g5 21.fxe6 Bxe6 22.Nf5 0–0–0 22.. Bxf5 best. 23.Nd6+ Rxd6 Exchange sack #2. 24.exd6 Qa3 25.Bf2 Qxd6 26.Bg3 Qd7 27.Rf6 Ne7 28.Qa1 b6 29.Qa3 Kb7 30.Bf3 Ng8 31.Qf8 Qe7 [31…Nxf6 32.Qxh8 Nxg4 33.Bxg4 Bxg4 34.Qxh6 Qe7–+] 32.Qb8+ [32.Bxd5+!! Bxd5 33.Qb8+ Ka6 34.Qc8+ Qb7 (34…Bb7?? 35.Qxc4+ mate in 4) 35.Qe8 Bc6 36.Qf8 Ba4 37.Rxf7 Nf6 38.Qg7 Ne8 39.Rxb7 Nxg7 40.Rxg7³] 32…Ka6 33.Rxe6 Exchange sack #3. 33…Qxe6 34.Kf2 f6 35.Qa8 Rh7? [35…Kb5 36.Bxd5 Ne7 37.Bxe6 (37.Qxh8 Nxd5–+) 37…Rxa8–+] 36.Bxd5 Qd7 37.Qxg8 Re7 38.Bxc4+ b5 39.Be2 Qc6 40.c4? [40.Qb3+-] 40…Rxe2+ Exchange sack #4. 41.Kxe2 Qe4+ 42.Kf1 Qf3+ 43.Ke1 Qe3+ 44.Kd1 Qxd4+ 45.Kc1 Qa1+ 46.Kd2 Qd4+ 47.Ke2 Qe4+ 48.Kf2 Qxc2+ 49.Ke3 Qc3+ 50.Ke4 Qc2+ (Diagram)


51.Kf3 [51.Kd4!! Fritz, with its inhuman precision, thinks White can escape the checks and win. 51…Qd2+ 52.Kc5 Qe3+ 53.Kc6 Qb6+ 54.Kd5 Qb7+ 55.Kd4 Qd7+ 56.Kc3+-] 51…Qd3+ 52.Kg2 Qe2+ 53.Kg1 Qd1+ 54.Kf2 Qd2+ 55.Kf1 Qd3+ 56.Kf2 Qd2+ 57.Kf3 Qd3+ 58.Kf2 Qd2+ ½–½

Twenty-one moves of theory!

Perez,R (2041) – Kerr,J (1913) [B79]

Queens CC Jamaica (4), 29.10.2004

1.e4 c5 2.Nf3 d6 3.d4 cxd4 4.Nxd4 Nf6 5.Nc3 g6 6.Be3 Bg7 7.f3 0–0 8.Bc4 Nc6 9.Bb3 Bd7 10.Qd2 Ne5 11.0–0–0 Qa5 12.Kb1 Rfc8 13.h4 Nc4 14.Bxc4 Rxc4 15.Nb3 (See the note at this point in Sugar-Sylvers of the current round). 15.. Qc7 16.Bd4 Be6 17.h5 a5 18.a4 Rb4 19.hxg6 hxg6 20.Rh4 Rc8 21.Rdh1 Amazingly, this has all been done before in Tiviakov (2655) – Phillips (2245) in the 1998 European Cup. Black continued with 21.. Bxb3 and lost in 29. 21…Qc4 [21…b5! 22.Nxb5 Qxc2+ 23.Qxc2 Rxc2 24.Kxc2 Bxb3+ equal, according to Fritz.] 22.g4 Rxa4 23.Qh2 Nh5 24.Bxg7 Kxg7 25.gxh5 Rb4 26.hxg6 fxg6 27.Rh7+ Kf8 28.Rh8+ Bg8 29.Qh6+ Ke8 30.Qxg6+ Kd7 31.Qf5+ Be6 32.Rxc8 Qxc8 33.Qxa5 Rc4 34.Qb5+ Kc7 35.Nd5+ Bxd5 36.Qxd5 Kb8 37.Rg1 1–0

Lorenzo,A (1800) – Kleinman,J (1820) [C45]

Queens CC Jamaica (4), 29.10.2004

1.e4 e5 2.Nf3 Nc6 3.d4 exd4 4.Nxd4 Qh4 The Steinitz Variation of the Scotch is generally frowned upon by theory. Black picks up a pawn or White ties himself up to keep it. Most theorists, though, think White’s play for the pawn is more than adequate, so the Steinitz is best saved for ‘once in a blue moon’ surprises. 5.Nxc6 5 Nc3 Bb4, 6 Nb5 is the usual procedure. 5…Qxe4+ 6.Be2 Qxc6 7.0–0 Bc5 8.Re1 Ne7 9.Bf3 Qb6 10.Qe2 0–0 11.Nc3 Nf5 12.Be4 Nd4 13.Qd3 f5 14.Bd5+ Ne6 15.Qf3 c6 16.Bb3 d5 17.Na4 Qa5 18.Nxc5?? Qxe1# 0–1

Drazil,F (1561) – Murphy,R (1949) [B45]

Queens CC Jamaica (4), 29.10.2004

1.e4 c5 2.Nf3 e6 3.d4 cxd4 4.Nxd4 Nf6 5.Nc3 Nc6 6.Be3 Bb4 7.f3 d5 8.Nxc6 bxc6 9.e5 Nd7 10.f4 Qa5 11.Bd2 Ba6 11.. Qb6 is Feio (2200) – Chernov (2405), Elista 1998, 0–1 in 16. 12.Qf3 0–0 13.a3 f6 14.Bxa6 Qxa6 15.Rd1 15 Qd3 leaves Black with just a slight edge. 15…Bc5 [15…Bxc3! 16.Qxc3 (16.Bxc3 fxe5–+) 16…fxe5 17.fxe5 Rf5–+] 16.b4 Bb6 17.b5 [17.exf6 Nxf6 (17…Rxf6 18.a4³) 18.Qe2³] 17…Qb7 18.Qh3 Rae8 19.exf6 Rxf6 20.Na4? e5 21.f5 cxb5 22.Nxb6 Qxb6 23.Bg5 Rd6 24.Be3 d4 25.Bf2 Qc6 26.0–0 Nb6 27.Qh5 Nd5 28.Rfe1 Nf6 29.Qe2 Qc4 30.Qd2 Rc6 31.Re2 Qc3 32.Qc1 d3 33.Re3 Qxc2 34.Ree1 Ng4 35.Bxa7 Qxc1 36.Rxc1 d2 0–1

Blake,B (1822) – DiStefano,V (1504) [C70]

Queens CC Jamaica (4), 29.10.2004

1.e4 e5 2.Nf3 Nc6 3.Bb5 a6 4.Ba4 Bc5 5.0–0 b5 6.Bb3 Nf6 7.d3 d6 8.Bg5 h6 9.Bh4 g5 10.Bg3 Bg4 11.c3 Nh5 11.. Bb6 has been played previously in this position. 12.Bd5 Qd7 13.d4 Nxg3 14.fxg3 Fritz wants 14 hxg3. The text creates a weakness for White along the g1–a7 diagonal. 14…exd4 15.cxd4 [15.b4 Bb6 16.Kh1 Ra7³] 15…Bxd4+ Black recaptures with the wrong piece. If he used the knight instead of the bishop, he’s winning. Now he’s losing. [15…Nxd4!! 16.Kh1 (16.Bxa8? Nxf3+–+; 16.Nxd4? Bxd1 17.Bc6 Bxd4+–+) 16…c6–+] 16.Nxd4 Nxd4 17.Qxd4 0–0 18.Bxa8 Rxa8 19.Nc3 c5 20.Qf6 Be6 21.Nd5 Bxd5 22.exd5 Kh7 23.Qxf7+ Qxf7 24.Rxf7+ Kg6 25.Rd7 a5 26.Rxd6+ 1–0

Sugar,Z (1759) – Sylvers,M (1459) [B79]

Queens CC Jamaica (4), 29.10.2004

1.e4 c5 2.Nf3 d6 3.d4 cxd4 4.Nxd4 Nf6 5.Nc3 g6 6.f3 Bg7 7.Be3 0–0 8.Qd2 Nc6 9.Bc4 Bd7 10.h4 Qa5 11.0–0–0 Ne5 12.Bb3 Rfc8 13.g4 Nc4 14.Bxc4 Rxc4 15.Kb1 Small world in chess. The position is nearly identical to Perez-Kerr (current round) at the same point, except that White there played Nb3 instead of g4. Rxc3? Thematic but premature. If Black has to trade queens in order to disrupt White’s pawn structure, then he doesn’t have enough left with which to attack and, therefore, not enough comp for the exchange. 15.. Rac8, as played previously in this position, was necessary first. 16.Qxc3 Qxc3 17.bxc3 Rc8 18.Ne2 18…Bb5 19.Nd4 Bc4 20.Rh2 Nd7 21.Nb3 Fritz prefers 21 h5. Now Black gets a chance for comp. 21…Bxc3 22.Bd4 Bb4 [22…Bxb3! 23.axb3 Bxd4 24.Rxd4 Ne5 25.Rh3 Rc3=] 23.f4 a5 24.h5 e5 25.Bb2 [25.Bxe5! Nxe5 26.fxe5 dxe5 27.hxg6 hxg6 28.Rdh1+-] 25…Nf6 26.a3 Bxb3 [26…Nxg4=] 27.cxb3 Bc3 [27…Nxg4=] 28.Rc2 Nxe4 29.Rdc1 Nd2+ 30.Ka2 [30.Rxd2+- but the text wins as well.] 30…Ne4 31.Bxc3 exf4 32.Bb2 Rxc2 33.Rxc2 f5 34.gxf5 gxf5 35.Rc4 Kf7 36.Rc7+ Ke6 37.Rxh7 f3 38.Bd4 Kd5 39.Bg1 b5 40.Re7 f2 41.Bxf2 Nxf2 42.h6 1–0

Swan,P (1411) – Denig,P (1620) [E10]

Queens CC Jamaica (4), 29.10.2004

1.d4 Nf6 2.c4 e6 3.Nf3 c5 4.d5 exd5 5.cxd5 d6 6.Bg5 Bg4 6.. Be7 is Keres-Rosenfeld (1960), 1–0 in 34. 7.Nbd2 Be7 8.h3 Bh5 9.e3? Hangs a pawn. 9…Nxd5 10.Bxe7 Nxe7 11.Bb5+ Nbc6 12.0–0 0–0 13.Qc2 Bg6 14.Bd3? Hangs a piece. 14…Nb4 15.Qb3 Bxd3 16.Rfe1 Bg6 17.e4 b6 18.a3 Nbc6 19.Nh4 Nd4 20.Qd1 Re8 21.Rc1 Kh8 22.Ndf3 Bh5 23.Rc3 Nec6 24.g4 Nxf3+ 25.Nxf3 Bg6 26.Rce3 Qf6 27.h4 h6 28.g5 Qf4 29.Qd5 Rac8 30.e5 dxe5 31.Nxe5 Nxe5 32.Rxe5 Rxe5 33.Rxe5 Qg4+ 34.Kf1 Qxh4 35.gxh6 Qxh6 36.b4 cxb4 37.axb4 Qc1+ 38.Re1 Qc4+ 39.Qxc4 Rxc4 40.b5 Rc7 41.Kg2 Bd3 42.Re5 f6 43.Rh5+ Kg8 44.Rd5 Be4+ 0–1

Bauer,A (1600) – Ryba,N (991) [B22]

Queens CC Jamaica (4), 29.10.2004

1.e4 c5 2.c3 d6 3.d4 cxd4 4.cxd4 Nf6 5.Nc3 g6 6.f4 Bg7 7.Nf3 0–0 8.Bd3 Re8 8.. Bg4 was played previously here. 9.0–0 Nbd7 Fritz prefers 9.. Nc6. Black gets a very cramped game now. 10.a4 e5 11.Nb5 exf4 11.. d5 better. 12.Nxd6 Re6 13.e5 Ne8 14.Ne4 Qb6 15.a5 Qd8 16.Bxf4 Nc7 17.Qb3 h6 18.Bc4 Re7 19.Nd6 Ne6 20.Nxf7 Kxf7 21.Nh4 Nxe5 22.Bxe5+ Kg8 23.Nxg6 Re8 24.Qf3 Qd7 25.Qg3 Bxe5 26.Nxe5+ Qg7 27.Qxg7+ Kxg7 28.Rf3 Ng5 29.Rg3 Kh7 30.Bd3+ Kg8 31.h4 1–0

Frawley,J (1722) – Rice,B (1512) [D50]

Queens CC Jamaica (4), 29.10.2004

1.d4 Nf6 2.c4 e6 3.Nc3 Bb4 4.Bg5 d5 5.e3 0–0 6.Nf3 c5 7.dxc5 Bxc3+ 7.. Nc6 is Hebert (2465) – Grodin (2250), Montreal 1997, drawn in 41. The text leads to the loss of a pawn. 8.bxc3 Nbd7 9.cxd5 Nxc5 10.dxe6 Qxd1+ 11.Rxd1 fxe6 12.Bxf6 Rxf6 13.Rd8+ Rf8 14.Rxf8+ Kxf8 15.Nd2 Fritz prefers going forward with 15 Ne5. 15…b6 16.Be2 Na4 17.Bf3 Rb8 18.Ne4 Ba6 19.Kd2 Rd8+ 20.Kc2 20 Kc1 is Fritz’s recommendation for White to hang on to a very small edge. 20…Bd3+ 21.Kb3 Bxe4 22.Kxa4 Bxf3 23.gxf3 Rd2 24.Rf1 Rxa2+ 25.Kb3 Ra5 26.Rg1 Rc5 27.Rg4 h6 28.h4 a5 29.Rd4 Ke7 30.c4 Rf5 31.Rg4 Kf7 32.f4 e5 33.fxe5 Rxf2 34.Rf4+ Rxf4 35.exf4 g6 36.Ka4 Ke6 37.Kb5 g5 38.hxg5 hxg5 39.fxg5 Kxe5 40.c5 bxc5 41.Kxc5 ½–½

Ryba,A (1149) – Chernick,S (1625) [B01]

Queens CC Jamaica (4), 29.10.2004

1.e4 d5 2.exd5 Qxd5 3.Nc3 Qa5 4.Nf3 Bg4 5.Be2 Nf6 6.h3 Bxf3 7.Bxf3 Qe5+ 7.. c6 is the book move here. 8.Qe2 Qxe2+ 9.Nxe2 c6 10.d4 e6 11.Be3 Nd5 12.Bxd5 cxd5 13.0–0 Nd7 14.Rac1 Bd6 15.c4 dxc4 16.Rxc4 Nb6 17.Rc2 Nd5 18.Rfc1 0–0 19.a3 Nb6 20.Nc3 a6 20.. Rac8= 21.Ne4 Rfd8 22.Nxd6 Rxd6 23.Rc7 Rad8 24.Rxb7 Nd5 25.Rb3 h6 26.Rc5 g5 27.Bd2 Kg7 28.Bc3 Kg6 29.Rb7 R8d7 30.Rxd7 Rxd7 31.Rc6 Ra7 32.g4 Nf4 33.Kh2 h5 34.gxh5+ Kxh5 35.Kg3 a5 36.Rc5 a4 37.Re5 Nd5 [37…f6 38.Rb5 Nd5= Black has neutralized White’s extra pawn here.] 38.Bd2 f5 39.Rxe6 Rb7 40.Bc1 Rb3+ 41.Kg2 Nf4+ 42.Bxf4 gxf4 43.Ra6 Rxb2 44.Rxa4 Rb3 45.d5 Kg5 46.Rd4 Rxa3 47.d6 Ra8 48.d7 Rd8 49.Kf3 Kf6 50.Kxf4 Ke6 51.h4 Kf6 52.h5 Ke6 53.h6 1–0

Drazil,P (628) – Milerski,H (1400) [D00]

Queens CC Jamaica (4), 29.10.2004

1.d4 d5 2.e3 e6 3.Nf3 c5 4.Bd2 4 a3, 4 Nbd2, and 4 Bb5+ are the only moves the database has here. 4…Nc6 5.Bc3 Nf6 6.Be2 Be7 7.0–0 0–0 8.Nbd2 a6 9.Nb3 b6 10.a3 Ne4 11.Be1 c4 12.Nbd2 b5 13.c3 f5 14.Ne5 Nxe5 15.dxe5 Nc5 16.Nf3 f4 17.Nd4 Bd7 18.b4 fxe3? 19.f3? Bg5? 20.Bg3? Bh4? 21.bxc5 Bxg3 22.hxg3 Rc8 23.Qc1 Rxc5 24.Qxe3 Rc8 25.Nc2 a5 26.Nd4 Qb6 27.Rab1 Qa6 28.f4 Qa7 29.Rf3 Qc5 30.Ra1 b4 31.axb4 axb4 32.cxb4 Qxb4 33.Nc2 Qb2 34.Qc1 c3 35.Ba6 Ra8 36.Bd3 Rfb8 37.Rf1 And White lost on Move 43, the remainder no longer making sense. (I’m not sure a good part of the game made sense, but I just report what I get.) 0–1


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